Question

find the roots of the quadratic equation if its roots are real and equal 8x² + 2x - 3 =0​

Answer 1

Required Answer:-

Given:

• 8x² + 2x - 3 = 0

To find:

• The values of x.

Solution:

We have,

➡ 8x² + 2x - 3 = 0

We need to split 2 into two values such that sum of those values is 2 and their product is -24(8 × -3)

We found:

• 6 - 4 = 2
• 6 × -4 = -24

So,

➡ 8x² + 2x - 3 = 0

➡ 8x² + 6x - 4x - 3 = 0

➡ 2x(4x + 3) - 1(4x + 3) = 0

➡ (2x - 1)(4x + 3) = 0

By zero product rule,

➡ Either 2x - 1 = 0 or 4x + 3 = 0

➡ x = 1/2, -3/4

★ Hence, the values of x are 1/2 and -3/4

Answer:

• x = 1/2, -3/4