find the roots of the quadratic equation. if the roots exist
(iv) 9x^-6x+1=0
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Answer:
root = 3x - 1
Step-by-step explanation:
9x^2 - 6x + 1 = 0
9x^2 - 3x - 3x + 1 = 0
3x ( 3x - 1 ) - 1 ( 3x - 1 ) = 0
( 3x - 1 ) ( 3x - 1 ) = 0
( 3x - 1 )^2 = 0
root = 3x - 1
zero = 1/3
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