Question

find the roots of the quadratic equation of 2x² - 3x -5​

Answer 1

Answer:

O

Step-by-step explanation:

2X$x^{2}$+3x+1=0

Answer 2

$\huge\mathcal\color{purple}{AnSwEr}$

$\bf \color{purple} {2x}^{2} - 3x - 5 = 0 \\ \bf \color{purple} s = ( - 3) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: p = ( - 10) \\ \bf \color{purple} ( - 5 \: \: \: \:2) \\ \bf \color{purple} ( {2x}^{2} + 2x) + ( - 5x - 5) = 0 \\ \bf \color{purple} [2x(x + 1)] + [ - 5(x + 1)] = 0 \\ \bf \color{purple} (2x - 5)(x + 1) = 0 \\ \bf \color{purple} 2x - 5 = 0 \: \: \: \: \: or \: \: \: \: \: \: x + 1 = 0 \\ \bf \color{purple} x = \frac{5}{2} \: \: \: \: \: \: or \: \: \: \: \: x = - 1 \\ \sf \color{purple} \therefore The \: roots \: are \: \bf \frac{5}{2} \sf \: and \: \bf - 1$

$\huge\bold\color{purple}{Hope~it~helps..!!}$