Question

find the roots of the quadratic equation root 3 x square-2x x-root3=0​

Answer 1

Answer:

Step-by-step explanation:

$\sqrt{3} x^{2} -2x-\sqrt{3} =0\\x= 2+-\sqrt{2^{2}+4*3} \\=2+-\sqrt{4+12} \\=2+-\sqrt{16}\\=2+-4\\=-2 or 6$

Roots= -2 and 6

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