Question

find the roots of the quadratic equation root3xsquare-2x-root3=0​

Answer 1

Step-by-step explanation:

$\sqrt{3} x {}^{2} - 2x - \sqrt{3} \\ on \: splitting \: middle \: term \\ \sqrt{3 }{x}^{2} - 3x + x - \sqrt{3} \\ \sqrt{3} x(x - \sqrt{3)} + 1(x - \sqrt{3} ) \\ (\sqrt{3} x + 1)(x - \sqrt{3} ) \\ \alpha = \frac{ - 1}{ \sqrt{3} } or - \frac{ \sqrt{3} }{3} \\ \beta = \sqrt{3}$