Question

Find the roots of the quadratic equation
${25x}^{2} - 10ax \: + {a}^{2} - {16b}^{2} = 0$
by using factorization.
Can anyone answer me...??
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Answer 1

Answer:

roots of the equation[25x^2-10ax+a^2-16b^2

Step-by-step explanation:

D=b^2-4ac

D=(-10a)^2-4(25)(a^2-16b^2)

D=100a^2-100a^2+1600b^2

D=1600b^2

x=(-b+√d)/2a,(-b-√d)/2a

x={-(-10a)+√1600b^2}/2(25),{-(-10a)+√1600b^2}/2(25)

x=(10a+40b)/2,(10a-40b)/2

x=5a+20b,5a-20b

I hope this solution helps you❤