Question

find the roots of the quadratic equation
$3{x}^{2} - 2 \sqrt{6}x + 2 = 0$

Answer 1

3x^2- 2√6x+ 2=0
3x^2- √6x-√6x+2
√3x(√3x-√2)- √2(√3x-√2)
(√3x-√2) (√3x-√2)
either,
√3x-√2=0
x=√2/3
either,
√3x-√2=0
x= √2/3
therefore, the roots of 3x^2- 2√6x+2=0 are : √2/3, √2/3