Find the roots of the quadratic equation v3x2 - 2x - 13 = 0
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6
Answer:
2 + 2√10 2 - 2√10
_______ , ______
3 3
Step-by-step explanation:
3x² - 2x - 13 = 0
Here,
a = 3
b = - 2
c = - 13
D = b² - 4ac
= ( - 2 )² - 4 ( 3 ) ( - 13 )
= 4 - ( - 156 )
= 4 + 156
D = 160
x = - b ± √D
_______
2a
= - ( - 2 ) ± √160
___________
2 ( 3 )
= 4 ± 4√10
_______
6
= 4 + 4√10 4 - 4√10
_______ , _______
6 6
= 2 ( 2 + 2√10 ) 2 ( 2 - 2√10 )
__________ , __________
6 6
x = 2 + 2√10 2 - 2√10
_______ , ______
3 3
Therefore,
the roots of the quadratic equation v3x2 - 2x - 13 are
2 + 2√10 2 - 2√10
_______ , ______
3 3
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