Question

Find the roots of the quadratic equation x^2-3x-10=0 by factorisation method

Answer 1

The two roots of the equation $x^2-3x-10=0$ are -2 and 5.

Step-by-step explanation:

Given,

$x^2-3x-10=0$

We have to find the roots of the given quadratic equation by factorization method.

For this we have to split the product of 1st term and 3rd term in order to obtain the 2nd term.

$x^2-3x-10=0\\\\x^2-5x+2x-10=0\\\\x(x-5)+2(x-5)=0\\\\(x+2)(x-5)=0$

Here we get the two factors of $x^2-3x-10=0$ are $(x+2) and (x-5)$.

Now we solve to get the value of x.

$x+2=0\\x=-2$

Again,

$x-5=0\\x=5$

Hence The two roots of the equation $x^2-3x-10=0$ are -2 and 5.

Answer 2

Answer:

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