Math, asked by Yashveer2004, 11 months ago

Find the roots of the quadratic equation x^2+5x-(a+1)(a+6)=0?

Answers

Answered by khadijaara456

2

Step-by-step explanation:

x2+(a+6)x-(a+1)x-(a+1)(a+6)=0

x (x+a+6)-a-1 (x+a+6)=0

(x+a+6)(x-a-1)=0

x= -(a+6),x=a+1

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