Question

Find the roots of the quadratic equation x^2+5x-(a+1)(a+6)=0?​

Answer 1

Step-by-step explanation:

x2+(a+6)x-(a+1)x-(a+1)(a+6)=0

x (x+a+6)-a-1 (x+a+6)=0

(x+a+6)(x-a-1)=0

x= -(a+6),x=a+1