Question

find the roots of the quadratic equation x^2 - x/5+1/100= 0

Answer 1

Here is your answer.

If you satisfied mark it as brainliest.

Answer 2

Answer: It has two equal roots as follows:

$x=\frac{1}{10},\ and\ \frac{1}{10}$

Step-by-step explanation:

Since we have given that

$x^2-\frac{x}{5}+\frac{1}{100}=0\\\\100x^2-20x+1=0$

We need to find the roots of the quadratic equation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{20\pm\sqrt{400-4\times 100\times 1}}{2\times 100}\\\\x=\frac{20-0}{200}\\\\x=\frac{1}{10},\frac{1}{10}$

Hence, it has two equal roots as follows:

$x=\frac{1}{10},\ and\ \frac{1}{10}$