Question

Find the roots of the quadratic
equation : (x+3)(x-1) =3(x - 1/3) ?
​

Answer 1

Step-by-step explanation:

(x+3)(x-1)=3(x-1/3)

x(x-1)+3(x+1)=3(3x-1/3)

x^2-x+3x-3=3x-1

x^2+2x-3=3x-1

x^2+2x-3x-3+1=0

x^2-x-2=0

α+β= -b/a

=-(-1)/1=1/1=1

αβ=c/a

= -2/1

=-2