find the roots of the quadratic equation x-3/x=2 by factorization
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Answered by
7
equation will be x2-1
using identity (a-b)(a+b)=a square-bsquare
factor will be (x+1)(x-1) is ur ans
using identity (a-b)(a+b)=a square-bsquare
factor will be (x+1)(x-1) is ur ans
Answered by
22
x -3/x = 2
(x^2 -3)/x = 2
x^2 - 3 = 2*x
x^2 -3 = 2x
x^2 -3 - 2x = 0
x^2 - 2x -3 = 0
x^2 - (3-1)x - 3 = 0
x^2 - 3x +x -3 = 0
x(x-3) + 1(x-3) = 0
(x-3) (x+1) = 0
Now,
x = 3 OR x = -1
the roots are 3,(-1)
i hope this will help you
-by ABHAY
(x^2 -3)/x = 2
x^2 - 3 = 2*x
x^2 -3 = 2x
x^2 -3 - 2x = 0
x^2 - 2x -3 = 0
x^2 - (3-1)x - 3 = 0
x^2 - 3x +x -3 = 0
x(x-3) + 1(x-3) = 0
(x-3) (x+1) = 0
Now,
x = 3 OR x = -1
the roots are 3,(-1)
i hope this will help you
-by ABHAY
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