Find the roots of the quadratic equation x-3\x to 2by factorization
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Given polynomial :
x - 3/x -2
(x² - 3 -2x )/x
( x² -3x + x -3 ) /x
= x ( x - 3 ) + 1 ( x - 3 ) / x
= ( x + 1 ) ( x - 3 ) / x
( x + 1 ) ( x - 3 ) / x = 0
( x + 1 ) ( x - 3 ) = 0
x = -1 , 3 .
Hope helped!
x - 3/x -2
(x² - 3 -2x )/x
( x² -3x + x -3 ) /x
= x ( x - 3 ) + 1 ( x - 3 ) / x
= ( x + 1 ) ( x - 3 ) / x
( x + 1 ) ( x - 3 ) / x = 0
( x + 1 ) ( x - 3 ) = 0
x = -1 , 3 .
Hope helped!
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0
Hi,
Please see the attached file!
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Please see the attached file!
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