Question

Find the roots of the quadratic equation (x + 6) ^2 = 64.

Answer 1

Step-by-step explanation:

$(x + 6) {}^{2} = 64$

$x {}^{2} + 12x + 36 = 64$

$x {}^{2} + 12x - 28$=0

${x}^{2} + 14x - 2x - 28$=0

$x(x + 14) - 2(x + 14)$=0

$(x - 2)(x + 14)$=0

THE ROOTS ARE 2 AND 14