Question

find the roots of the quadratic equation x2+5x-(alpha+1)(alpha+6)=0,:where:alpha is some constant... please help its urgent..
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Answer 1

solution is in attachment

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Answer 2

Answer:

Step-by-step explanation:

x2+5x-(n=1)(n+6)=0

x2-(p+1)x+(p+6)x-(p+1)(p+6)=0

x(x-p-1)+(p+6)(x-p-1)=0

(x-p-1)(x+p+1)=0

(x-p-1)=0 and (x+p+1)=0

x=p-1 and x=(-p-1)