Math, asked by pravatkumarparida612, 5 months ago

Find the roots of the quadratic equations 2x^2-3x-5=0

Answers

Answered by tajmohamad7719

Given equation is:

Given equation is:2x

Given equation is:2x 2

Given equation is:2x 2 +3x−5=0

Given equation is:2x 2 +3x−5=0By using quadratic formula,

Given equation is:2x 2 +3x−5=0By using quadratic formula,x=

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b±

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x=

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3±

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5)

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x=

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3±

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x=

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4−3±

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4−3± 49

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4−3± 49 ∴x=1,x=

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4−3± 49 ∴x=1,x= 2

Given equation is:2x 2 +3x−5=0By using quadratic formula,x= 2a−b± b 2 −4ac ∴x= 2(2)−3± 3 2 −(4)(2)(−5) x= 4−3± 9+40 x= 4−3± 49 ∴x=1,x= 2−5

Step-by-step explanation:

Answered by jiyasounderya

Answer:

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