Question

find the roots of the quadratic equations by applyinv the quadratic formula 2x^2-7x+3=0​

Answer 1

Answer:

Given equation :$2x^{2} -7x+3=0$

General form : $ax^{2} + bx +c=0 , D = b^{2} - 4ac$

→ $x=\frac{-b+\sqrt{D} }{2a}$

a=2 , b=-7, c=3

$D= b^{2} -4ac\\D=(-7)^{2} -4(2)(3)\\D= 49-24\\D=25$

$x=\frac{-(-7)+\sqrt{25} }{2(2)} \\\\x=\frac{7+5}{4} \\\\x= \frac{7+5}{4} , \frac{7-5}{4} \\\\x=\frac{12}{4} , \frac{2}{4} \\\\x=3,\frac{1}{2}$