Question

find the roots of the quadratic equations given in Q. 1 above by applying the quadratic formula
2x²-7x+3=0
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Answer 1

Step-by-step explanation:

2x2-7x+3

2x2-6x-x+3

2x(x-3)+1(x-3)

(x-3)(2x-1)

Answer 2

Step-by-step explanation:

2x² - 7 x + 3 =0

2x²-6x-x+3=0

2x(x-3)-1(x-3)=0

(2x-1) (x-3)

now ,

$2x = 1 \\ x = 1 \div 2$

$x - 3 = 0 \\ x = 3$

the roots of the following polynomial is equals to 1 by 2 and 3