Question

find the roots of the quadratic equations
$2x {}^{2} - 7x + 3 = 0$
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Answer 1

Answer:

$2 {x}^{2} - 7x + 3$

$2 {x}^{2} - 6x - x + 3 = 0$

$2x(x - 3) -1(x - 3) = 0$

$(2x - 1)(x - 3) = 0$

$2x - 1 = 0 \\ 2x = 1 \\ x = \frac{1}{2}$

$x - 3 = 0 \\ x = 3$

so they are two roots of given eqaution

Answer 2

Hi !

So simple question bache ,

2x² - 7x + 3 = 0

2x² - 6x - x + 3 = 0

2 x(x-3)- 1 ( x-3) = 0

(2x-1)((x-3) = 0

x = 1/2 and x = 3

1/2 and 3 are the roots of this quadratic equation.

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Hope this helps you !

@Rajkumar111