Question

find the roots of the quadratic equations x-1/X=3,x is not equal to 0​

Answer 1

Answer:

x

$x = (3 - \sqrt{13} ) \div 2 \\ or \\ x = (3 + \sqrt{13} ) \div 2$

Step-by-step explanation:

$x - 1 \div x = 3$

${x }^{2} - 1 = 3x$

${x}^{2} - 3x - 1 = 0$

So,

$x = (3 + \sqrt{ { ( - 3)}^{2} - 4 \times 1 \times ( - 1)} )\div (2 \times 1)$

Or

$x = (3 - \sqrt{ {( - 3)}^{2} - 4 \times 1 \times ( - 1d)}) \div (2 \times 1)$

$x = (3 + \sqrt{13} ) \div 2 \\ or \\ x = (3 - \sqrt{13}) \div 2$