Question

find the roots of the quadratic polynomial x²-3x+28=0​

Answer 1

Answer:

$The solutions are:x=−4,x=7Explanation:x2−3x−28=0We can first factorise this expression by splitting the middle term and then find the solutions:=x2−7x+4x−28=0=x(x−7)+4(x−7)=0=(x+4)(x−7)Now, we can equate the two factors with zero and find the solutions:x+4=0,x=−4x−7=0,x=7$

Step-by-step explanation:

Answer 2

Answer:

Factor pairs of (c = -28) -> (-2, 14)(-4, 7). This sum is 3 = -b. Then the 2 real roots are: -4 and 7.