Question

find the roots of the qudratic equation x2 -x/5+1/100=0​

Answer 1

Answer:

x²-x/5+1/100=0

=> 100x² - 20x + 1

=> 100x² -10x -10x + 1

=> 10x( 10x - 1) -1(10x - 1)

=>( 10x -1) (10x - 1)

=> x = 1/10 , x = 1/10

Answer 2

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$\sf x^2 -\dfrac{x}{5}+\dfrac{1}{100}=0 \\ \sf 100x^2-20x+1=0 \\ \sf 100x^2-10x-10x+1=0 \\ \sf 10x (10x-1) -1 (10x-1)=0 \\ \sf x=\dfrac{1}{10}\: or \:x=\dfrac{1}{10}$