Question

find the roots of this eqn . i give you 100 points for that
${x}^{2} - 4x - 3$

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Answer 1

Answer:

$x = \frac{4 + \sqrt{38} }{2} \: \: \: \: \: \: \: \: \frac{4 - \sqrt{38} }{2}$✔✔

Step-by-step explanation:

SOLUTION-

${x}^{2} - 4x - 3 \\ we \:use \:quadratic \: formla\: for \: this \: eqn \\ {x}^{2} - 4x - 3 \\ d = { {b}^{2} - 4ac } \\ d = {4}^{2} + 12 \\ d = 38 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{4 + \sqrt{38} }{2} \: \: \: \: \: \: \: \: \frac{4 - \sqrt{38} }{2}$

Answer 2

${x}^{2} - 4x - 3 \\ we \:use \:quadratic \: formla\: for \: this \: eqn \\ {x}^{2} - 4x - 3 \\ d = { {b}^{2} - 4ac } \\ d = {4}^{2} + 12 \\ d = 38 \\ x = \frac{ - b + - \sqrt{d} }{2a} \\ \: \: \: \: = \frac{4 + \sqrt{38} }{2} \: \: \: \: \: \: \: \: \frac{4 - \sqrt{38} }{2}$