Question

Find the roots of this quadratic equation
√3x^2+√3x+6√3

Answer 1

/3x^2 + /3x + 6/3 = 0
By Formula method
By comparing to
ax^2 + bx + c =0
a=/3 ; b=/3 ; c=6/3
Discriminant = b^2 - 4ac
= (/3)^2 - 4(/3 × 6/3)
= 3 - 4×6×3
= 3-72
= - 69

x = - b +/- (/b^2-4ac) / 2a
x = - /3 +/- (/-69) / 2×/3
x = - /3 +/- (/-69) / 2/3

1) x = - /3 + /-69 / 2/3

2) x = - /3 - /-69 / 2/3

Hope it helps you!!! ☺☺