Question

find the roots of this using quadratic formula

1/x+2    -        1/x=3 

Answer 1

(1/x+2)-1/x=3
3x²+6x+2=0

x= (-b+√b²-4ac)/2a or (-b-√b²-4ac)/2a
x= (-6+√36-24)/6 
x= (-6+√12)/6
x= (-6+2√3)/6
x= 2(-3+√3)/6
x= (-3+√3)/3

or
x= (-6-√36-24)/6 
x= (-6-√12)/6
x= (-6-2√3)/6
x= 2(-3-√3)/6
x= (-3-√3)/3