Question

find the roots of x^2 + 1 =0​

Answer 1

Answer:

no real roots

Step-by-step explanation:

$x^{2}$+1=0

$x^{2}$= -1

x=$\sqrt{-1}$

which is not possible because root of a -ve no. does't existes

hope it will help you

Answer 2

${x}^{2} + 1 = 0 \\ {x}^{2} = - 1 \\ x = \sqrt{ - 1} \\ x = i$