Question

find the roots of x^2-10x-2=0​

Answer 1

Answer:

Explanation:

x2+10x−2=0

Add 2 to both sides of the equation.

x2+10x=2

Force a perfect square trinomial on the left side of the equation.

Divide the coefficient of the x term and square the result. Add it to both sides of the equation.

(102)2=52=25

x2+10x+25=2+25 =

x2+10x+25=27

We now have a perfect square trinomial on the left side with the form a2+2ab+b2=(a+b)2.

a=x, b=5

(x+5)2=27

Take the square root of both sides.

(x+5)=±√27 =

x+5=±√3√9 =

x+5=±3√3 =

Subtract 5 from both sides.

x=−5±3√3

x=−5+3√3

x=−5−3√3

x=−