Question

Find the roots of (x - √2)² - 2(x + 1) = 0​

Answer 1

Answer:

X square +2-2x-2=0

Xsquare-2x+2-2=0

x-0=0

x=0

Answer 2

$(x-\sqrt{2} )^2-2(x+1)=0$

$\Leftrightarrow (x^2-2\sqrt{2} x+2)-(2x+2)=0$

$\Leftrightarrow x^2-2(\sqrt{2} + 1)x=0$

$\Leftrightarrow x\{x-2(\sqrt{2} + 1)\}=0$

By zero product rule,

$x=0$ or $x=2(\sqrt{2} + 1)$

Sorry for the incorrect information.

The triangle problem has a solution $x=5$ cm.

Kindly report it.