Find the roots of x^2+3x-2 by using general formula
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Answered by
0
Hey.....
D=b2-4ac
=3×3-4×1×(-2)
= 9+8
= 17
x=-b under root D/2a
x=-3 under root 17 /2
x=-3 plus minus under root 17 /2
if positive
x=-3 +root 17 /2
if negative
x= -3-root 17/ 2...
hope this helps u...
D=b2-4ac
=3×3-4×1×(-2)
= 9+8
= 17
x=-b under root D/2a
x=-3 under root 17 /2
x=-3 plus minus under root 17 /2
if positive
x=-3 +root 17 /2
if negative
x= -3-root 17/ 2...
hope this helps u...
Answered by
8
Equation :- x² + 3x - 2
a = 1
b = 3
c = -2
Roots by using quadratic formula
[Distinct Method]
___________________[Put Values]
D = (3)² - 4(1)(-2)
D = 9 + 8
D = 17
√D = √17
Quadratic Formula :-
______________[Put values]
x = -(3) ± √17 / 2(1)
When Positive(+)
x = -3 + √17 / 2
When negative (-)
x = -3 - √17 / 2
________________________
Or
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