Math, asked by hackermania1125, 10 months ago

find the roots of x^2-4 root2x+6=0

Answers

Answered by Anonymous
3

Answer:

GIVEN :

find the roots of x²- 42x + 6 = 0

SOLUTION :

x² - 42x + 6 = 0

x² - 32x - 2x + 6 = 0

x ( x - 32 ) -2 ( x - 32 ) = 0

( x - 32 ) ( x - 2 ) = 0

x - 32 = 0 ; x - 2 = 0

x = 0 + 32 ; x = 0 + 2

x = 32 ; x = 2

Therefore, the roots are 32 & 2

Step-by-step explanation:

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