find the roots of x^2 + 4x - 5 = 0 using quadratic formula
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x2 + 4x + 5 = 0. Here, a = 1, b = 4, c = 5. So, b2 – 4ac = 16 – 20 = – 4 < 0. Since the square of a real number cannot be negative, therefore √b2-4ac not have any real value.
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