Question

Find the roots of x^2 - 4x + 8 = 0 by the method of completing square

Answer 1

2
$2 + \sqrt{ - 16} and \: 2 - \sqrt{ - 16}$

Answer 2

hey mate ✋✋

here's your answer ⏩⏩

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$= > {x}^{2} - 4x + 8 = 0 \\ = > \frac{ {x}^{2} }{1} - \frac{4x}{1} + \frac{8}{1} = 0 \\ = > {x}^{2} - 4 \times x = - 8 \\ = > {x}^{2} - 4 \times x + ( {4 \times \frac{1}{2} })^{2} = - 8 +({4 \times \frac{1}{2} })^{2} \\ = > {x}^{2} - 4 \times x + ({ \frac{4}{2} })^{2} = - 8 + \frac{16}{4} \\ = > ({x - \frac{4}{2} })^{2} = \frac{ - 32 + 16}{4} \\ = > ( {x - \frac{4}{2} )}^{2} = \frac{ - 16}{4} \\ = > (x - \frac{4}{2} ) = \sqrt{ - 4} \\ = > x - \frac{4}{2} = \binom{ + }{ - } 2 \\ = > x = \binom{ + }{ - } 2 + \frac{4}{2}$\\

$= 2 + \frac{4}{2} \\ = \frac{4 + 4}{2} \\ = \frac{8}{2} \\ = 4 \\ \\ = 2 - \frac{4}{2} \\ = \frac{4 - 4}{2} \\ = \frac{0}{2} \\ = 0 \\ \\ therefore \: x = 4 \: or \: 0$


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