Math, asked by deepbrar9355, 10 months ago

Find the roots of x^2-4x-8=0 by the method of completing the square.

Answers

Answered by karishmarajak
1

Step-by-step explanation:

x²-4x-8=0

x²-4x=8

x²-2x×2=8

Adding coefficient of (x)²

x²-4x+(2)²=8+(2)²

(x-2)²=12

squaring both sides

x-2=√12

x=√12+2

x=√12-2

Please mark it as brainliest

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