Find the roots of x^2-4x-8 by the method of completing square
Answers
Answered by
1
hope this helps and if there's any doubt ask freely
Attachments:
Answered by
0
x²-4x-8=0
x= (-b±√b²-4ac)/2a
={4±√(-4)²-4*1*(-8)}/2*1
=(4±√16+32)/2
=(4±√48)/2
=(4±4√3)/2
=2(2±2√3)/2
=2±2√3
x= (-b±√b²-4ac)/2a
={4±√(-4)²-4*1*(-8)}/2*1
=(4±√16+32)/2
=(4±√48)/2
=(4±4√3)/2
=2(2±2√3)/2
=2±2√3
Similar questions