Find the roots of - = , x ≠ -4, 7
OR
Find the nature of the roots of 2x2 - 6x + 3 = 0. If the real roots exist find them.
Answers
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1
Step-by-step explanation:
p(x)=2x^2-6x+3=0
D=b^2-4ac
=(-6)^2-4(2)(3)
=36-24
=12
the roots are real
x=-b+-√D/2a
=6+-√12/4
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