Math, asked by kesar48, 4 months ago

Find the roots of - = , x ≠ -4, 7
OR
Find the nature of the roots of 2x2 - 6x + 3 = 0. If the real roots exist find them.

Answers

Answered by srutidk2005
1

Step-by-step explanation:

p(x)=2x^2-6x+3=0

D=b^2-4ac

=(-6)^2-4(2)(3)

=36-24

=12

the roots are real

x=-b+-√D/2a

=6+-√12/4

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