Math, asked by annusaini1298, 10 months ago

find the roots of x^4-x^2+1=0​

Answers

Answered by royb83013
1

Step-by-step explanation:

x⁴-x²+1=0

let, x²= t

then, t²-t+1=0

t = t±√t²-4t²/2t²

since, it has no root because √-3t² which is a imaginary part

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