Find the roots of x square - 2 x minus a square minus one
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Given: The equation x square - 2 x minus a square minus one
To find: The roots of the given equation.
Solution:
- Now we have given the equation as:
x^2 - 2x - (a^2 - 1) = 0
- The roots will be:
-b ± √(b^2 - 4(ac)) / 2a
- So applying this formula, we get:
-(-2) ± √((-2)^2 - 4(1)(a^2 - 1)) / 2
- Now simplifying this, we get:
2 ± √( 4 - 4a^2 + 4 ) / 2
2 ± √( 8 - 4a^2 ) / 2
2 ± √4( 2 - a^2 ) / 2
2 ± 2√( 2 - a^2 ) / 2
- Cancelling 2, we get:
1 ± √( 2 - a^2 )
Answer:
So the roots of the given equation is 1 ± √( 2 - a^2 ) .
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