Question

find the roots of x square - 3 x minus 1 is equal to zero by using quadratic formula​

Answer 1

this is all about the answer

Answer 2

The zeros of the quadratic equation are $x=\frac{3+\sqrt{13}}{2},\:x=\frac{3-\sqrt{13}}{2}$

Step-by-step explanation:

The given quadratic equation is

$x^2-3x-1=0$

For this equation,

a = 1, b = -3 and c = -1

The quadratic formula for finding the zeros is given by

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substituting the known values, we get

$x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\left(-1\right)}}{2\cdot \:1}\\\\=\frac{3\pm\sqrt{13}}{2\cdot \:1}\\\\x=\frac{3+\sqrt{13}}{2},\:x=\frac{3-\sqrt{13}}{2}$

#Learn More:

Zeros by using quadratic formula​

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