Question

find the roots of x square + 4 x + 5 is equal to zero by using formula​

Answer 1

Answer:

$x=-2\frac{+}{}i$

Step-by-step explanation:

$x^2+4x+5=0$

Quadratic Formula $_1$ : $x=\frac{-b'\frac{+}{}\sqrt{b'^2-ac} }{a}$

$x=\frac{-2\frac{+}{}\sqrt{4-5} }{1}$

∴$x=-2\frac{+}{}i$

Quadratic Formula $_2$ : $x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-4\frac{+}{}\sqrt{16-20} }{2}$

∴$x=\frac{-2\frac{+}{} 2i}{1} =-2\frac{+}{} i$