find the roots of x²-1 = 8(x-1)
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Answer:
x²-1 = 8(x-1)
x² -1 = 8x - 8
x² - 8x +8-1=0
x² - 8x +7 = 0
x² - (7x+1x) +7 = 0
x² -7x - x + 7 = 0
x(x-7) -1(x-7) = 0
(x-7)(x-1) = 0
x = 7, or 1
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