find the roots of x²-4x-8=0 by completing the square
Answers
Answered by
56
x²-4x -8 = 0
x²-4x = 8
x²-4x+4 = 8+4 = 12
(x-2)² = 12
x-2 =√12 = +2√3 or -2√3
x = -2√3+2 or x = 2√3+2
hence, x+2√3-2 = 0
x-2√3-2 = 0
x²-4x = 8
x²-4x+4 = 8+4 = 12
(x-2)² = 12
x-2 =√12 = +2√3 or -2√3
x = -2√3+2 or x = 2√3+2
hence, x+2√3-2 = 0
x-2√3-2 = 0
ramandeep28:
but where is the answerrr
in solution, its given 2±2√3
Similar questions