find the roots of x2-9x+14=12
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Answer:
obtain zeros P(x)=x
2
+9x+14
→ for zeros find P(x) = 0
x
2
+9x+14=0
x
2
+7x+2x+14=0
x(x+7)+2(x+7)=0
(x+7)(x+2)=0
x=−7 or x=−2
zeros is -7 & -2
→P(−7)=(−7)
2
+9(−7)+14
=+49−63+14
=0
→P(−2)=(−2)
2
+9(−2)+14
=4−18+14
=0
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