find the roots of x²+px+16 are equal and find p
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Answered by
0
Answer:
- 8
Step-by-step explanation:
Let the roots be 'a' and 'a'. Comparing this with ax² + bx + c,
a = 1 , b = p, c = 16 {this a is different from that in question}
Product of roots = c/a = 16/1
a * a = 16
a² = 16
a = 4
Sum of roots = -b/a
a + a = - p/1
4 + 4 = - p
- 8 = p
Answered by
3
Answer:
-8
Step-by-step explanation:
hope it is help you☺️✍️
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