Question

Find the roots of x2 + x - 6 - 0 by the method of factorisation​

Answer 1

Answer:

x2+3x-2x+6=0

x(x+3) -2(x+3) =0

(x+3) (x-2) =0

x=-3;x=2

Answer 2

Answer:

${x}^{2} + x - 6 = 0$

${x}^{2} + 3x - 2x - 6 = 0$

$x(x + 3) - 2(x + 3) = 0$

$(x - 2)(x + 3) = 0$

$x - 2 = 0 \\ x = 0 + 2 \\ x = 2$

Or

$x + 3 = 0 \\ x = 0 - 3 \\ x = - 3$

Negative value is not accepted.

x = 2