Question

Find the roots of x2-x-a(a+1)=0​

Answer 1

Answer:

hey mate here is the answer

Step-by-step explanation:

x²-x(a+1)+ax-a(a+1)=0

x{x-a+1} +a(x-(a+1) = 0

(x+9) { x-(a+1)}=0

x+a=0

x= -a

x-(a+1)=0

x= a+1

ANSWER - x = -a and x= a+1

Answer 2

Step-by-step explanation:

Given: x2 – x –a(a + 1) = 0 ⇒ x2 – x – a2 – a = 0 ⇒ (x2 – a2 ) – (x + a) = 0 ⇒ (x + a)(x – a) – (x + a) = 0 [∵ a2 – b2 = (a + b)(a - b) ] ⇒ (x + a)[(x – a) – 1)] = 0 ⇒ (x + a) = 0 or (x – a) – 1 = 0 ⇒ x = – a or x = (a + 1)