Question

find the roots of x²+x-p(p+1)=0

Answer 1

=x^2 + x - p^2 - p

=x^2 - p^2 +x - p

=(x+p)(x-p) +(x-p)(1) [a^2-b^2=(a+ b)(a-b)]

=(x-p)(x+p+1) ANSWER