Question

find the roots of : -
z² + 2√2z - 6=0​

Answer 1

Given equation

$z^{2} +2\sqrt{2}x - 6 = 0$

Solving, we get,

$z^{2} + 2\sqrt{2} x - 6 = 0\\\implies z^{2} +3\sqrt{2}z - \sqrt{2}z - 6 = 0\\ \implies z(z+3\sqrt{2})-\sqrt{2} (z+3\sqrt{2})=0 \\\implies (z-\sqrt{2})(z+3\sqrt{2}) = 0$

$z - \sqrt{2}=0\\ \boxed{\boxed{\bold{z=\sqrt{2}}}}}$

$z+3\sqrt{2}= 0\\ \boxed{\boxed{\bold{z = -3\sqrt{2}}}}}$

                                                     

Answer 2

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