Question

find the roots: x ^ 7 - x ^ 4 + x ^ 3 - 1 = 0​

Answer 1

x=1

Step-by-step explanation:

x^7-x^4+x^3 -1 =0

x^4 (x^3 -1) +( x^3 -1) =0

(x^3 -1) (x^4 +1) =0

x^3 -1 =0 or x^4 +1=0

x^3 =1 or x^4 = -1

x =cube root 1

x= 1