Question

find the roots x square-3x+2=0​

Answer 1

$\huge\star \: \: \: \: \: {\huge{\bold{\red{\underline{SOLUTION: }}}}}$

${x}^{2} - 3x + 2 = 0 \\ = >x = \frac{ - ( - 3) + - \sqrt{ {3}^{2} - 4 \times 1 \times 2} }{2 \times 1} \\ \: \\ = > x1 = 2 \: \: \: \: \: \: \: \: \: \\ x2 = 1$

$\huge\boxed {x1 = 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ x2 = 1}$

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